Sorry this post is a little late.. I never had time yesterday and today it took me awhile to upload images due to the sweet sun computers.
Anywho, today Mr. Maksymchuk continued on his journey to explain identities. Today we did some more work with double angle identities. As shown below, Mr. Max took all the equations given to us in our exam formula sheet and showed how they derived the formula. I found this part very helpful and makes learning identities easier to understand!
Another things that I found useful in today's lesson is to always keep in mind the key triangles that we learned at the start of the year. Also take not of a 30, 60, 90 triangle with lengths of 3, 4, and a hypotenuse of 5. Knowing these triangles will come in very handy.
In this picture below, they wanted to know the value of 2(theta). So Max simply input the values for theta into another formula from our exam formula sheet, and solved for cosine and sine. Always note the signs you apply to the final answer so you make sure you have it in the right quadrant.
Below is just another example of solving double angles using exact values. Remember to FACTOR out like terms!!!
Well this is the end of my post. Any questions or comments on how I can improve PLEASE let me know. Thank you for your time.
Remember!!! Always keep the stick on the ice.
Love Cramer
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